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+--- Thread: Here's a math problem for you (/showthread.php?tid=2589)
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RE: Here's a math problem for you - Paradox - 04-09-2011
(04-09-2011, 01:28 AM)Jacob_ Wrote: What is the second derivative of f(x) = 4x^2+2x+1?
If you get it right, you get....the satisfaction of having solved an advanced math problem!
f(x) = 4x^2+2x+1
f'(x) = 8x+2
f''(x) = 8
RE: Here's a math problem for you - Scripter - 04-09-2011
I'm guessing I got the x-intercept problem right, so cheers!
Now when will this be moved to General Discussion? ^_^
RE: Here's a math problem for you - Jacob__mybb_import1 - 04-09-2011
(04-09-2011, 02:02 AM)Paradox Wrote:(04-09-2011, 01:28 AM)Jacob_ Wrote: What is the second derivative of f(x) = 4x^2+2x+1?
If you get it right, you get....the satisfaction of having solved an advanced math problem!
f(x) = 4x^2+2x+1
f'(x) = 8x+2
f''(x) = 8
Correct! For those just reading the thread, give Paradox and Scripter rep points.