Here's a math problem for you
#1
What is the second derivative of f(x) = 4x^2+2x+1?

If you get it right, you get....the satisfaction of having solved an advanced math problem!
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#2
Using all the power of my mind im able to say that those are numbers :P
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#3
*looks at math problem*
Dont you have something a little bit easier?
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#4
y=4x+1

What is the x-intercept?
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#5
i cant :B
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#6
I'm no good at calc, mostly because I never attempted to learn much of it. Using my quickly googled question however, I think I know how to get the derivative.
4x^2+2x+1
4x^2 + 2x
(2)4x^2 + 2x
8x^2 + 2x
8x + 2x
10x

Eh...that doesn't make sense. I'm going to try and learn it from a book instead of from ehow


And x-intercept?
y = 4x + 1
0 = 4x + 1
-1 = 4x
-1/4 = x

Is it -1/4? o.o
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#7
(04-09-2011, 01:28 AM)Jacob_ Wrote: What is the second derivative of f(x) = 4x^2+2x+1?

If you get it right, you get....the satisfaction of having solved an advanced math problem!

I'll solve it for what I THINK is it.
f(2) = 2^2 = 4*4 = 16 .
f(2) = 2*2 = 4 + 16 = 20 + 1 = 21.

f(2) = 21
{(2, 21)}
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#8
x= y-1 : 4

I got it? Big Grin
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#9
My Robotic mind has fried, I think I need a new motherchip.
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#10
(04-09-2011, 01:33 AM)Scripter Wrote: I'm no good at calc, mostly because I never attempted to learn much of it. Using my quickly googled question however, I think I know how to get the derivative.
4x^2+2x+1
4x^2 + 2x
(2)4x^2 + 2x
8x^2 + 2x
8x + 2x
10x

Eh...that doesn't make sense. I'm going to try and learn it from a book instead of from ehow


And x-intercept?
y = 4x + 1
0 = 4x + 1
-1 = 4x
-1/4 = x

Is it -1/4? o.o

Scripter got it right. Everyone, give him + rep points!

Login, the first problem is a calculus one... you probably haven't learned it yet.
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