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How about a random math debate?
#11
Wait, why is it i? How does 1/0 = sqrt(-1)?
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#12
(05-09-2012, 09:02 PM)noob007 Wrote: Wait, why is it i? How does 1/0 = sqrt(-1)?

i = Unknown/impossible digit.
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#13
(05-09-2012, 09:02 PM)noob007 Wrote: Wait, why is it i? How does 1/0 = sqrt(-1)?

Because i is an imaginary number (It isn't a real number).
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#14
(05-09-2012, 09:02 PM)noob007 Wrote: Wait, why is it i? How does 1/0 = sqrt(-1)?

Because 0 is the scientific root to 1.
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#15
(05-09-2012, 09:04 PM)Franco30557 Wrote:
(05-09-2012, 09:02 PM)noob007 Wrote: Wait, why is it i? How does 1/0 = sqrt(-1)?

Because 0 is the scientific root to 1.

No, 1 is the square root of 1...
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#16
i is imaginary, yet that doesn't mean 1/0 is imaginary... it can be any number, right? That's why they call it undefined. I think you could also say 1/0 = ∞.
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#17
i = 1/0

So... i + i = ????
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#18
(05-09-2012, 09:09 PM)Franco30557 Wrote: i = 1/0

So... i + i = ????

i+i=2i
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#19
(05-09-2012, 09:06 PM)noob007 Wrote: i is imaginary, yet that doesn't mean 1/0 is imaginary... it can be any number, right? That's why they call it undefined. I think you could also say 1/0 = ∞.

You have a point. When dividing 1 by 0 is pretty much the same as dividing by ∞. That could be any number starting in 1-9, so it could be:
1
.5
.333
.25
.2
.1667
.142
.125
.1

Then followed by a recurring amount of numbers between 0-9, which would still give you a number between 0-1, unless that number is a recurring 0, then you get caught in a paradox.
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#20
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