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How about a random math debate?
#21
(05-09-2012, 09:10 PM)Kieron Wrote:
(05-09-2012, 09:06 PM)noob007 Wrote: i is imaginary, yet that doesn't mean 1/0 is imaginary... it can be any number, right? That's why they call it undefined. I think you could also say 1/0 = ∞.

You have a point. When dividing 1 by 0 is pretty much the same as dividing by ∞. That could be any number starting in 1-9, so it could be:
1
.5
.333
.25
.2
.1667
.142
.125
.1

Then followed by a recurring amount of numbers between 0-9, which would still give you a number between 0-1, unless that number is a recurring 0, then you get caught in a paradox.

What now? i is imaginary. If 1/0 = ∞, that means 7253753 = ∞
=(
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#22
New topic: x + y = z?
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#23
(05-09-2012, 10:39 PM)Franco30557 Wrote: New topic: x + y = z?

Impossible to solve.
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#24
it's possible, and has over 9000 solutions.
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#25
It actually is solvable, but it has infinitely many solutions and you have to use linear algebra.

[Image: CP656.gif]

(This might not be correct, my class didn't cover how to solve systems of equations with no basic variables...)
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#26
x/0 = SYNTAX ERROR
[Image: paperboy.PNG]
True beauty.
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#27
x = x
y = y
x + y = z
----------
It's really easy to solve...
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#28
(05-10-2012, 05:56 PM)Franco30557 Wrote: x = x
y = y
x + y = z
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It's really easy to solve...

You can't add 2 letters -.-
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#29
(05-10-2012, 05:58 PM)Kieron Wrote:
(05-10-2012, 05:56 PM)Franco30557 Wrote: x = x
y = y
x + y = z
----------
It's really easy to solve...

You can't add 2 letters -.-

I don't see you thinking of an equation... -_-

x can be anything, y can be anything; which will each give the value of z
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#30
(05-10-2012, 06:02 PM)Franco30557 Wrote: I don't see you thinking of an equation... -_-

x can be anything, y can be anything; which will each give the value of z

X and Y variable can be anything, and I'm pretty sure they don't have to add up to Z variable.
[Image: paperboy.PNG]
True beauty.
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